Questions
We are playing the Guess Game. The game is as follows:
I pick a number from 1
to n
. You have to guess which number I picked.
Every time you guess wrong, I will tell you whether the number I picked is higher or lower than your guess.
You call a pre-defined API int guess(int num)
, which returns three possible results:
-1
: Your guess is higher than the number I picked (i.e.num > pick
).1
: Your guess is lower than the number I picked (i.e.num < pick
).0
: your guess is equal to the number I picked (i.e.num == pick
).
Return the number that I picked.
Algorithm
The trivial solution is you try each number each time and check if it's the one you want. However, this will waste the guess()
.
Guess function not only return if the number is what we want, but also can tell us it's higher and lower. And we are give a numbers from 1 to n which is sorted. Comparing, sorted numbers, these may lead you to the binary search.
Since we don't have a target to compare, but we do have guess()
who can direct us, so we still can decide which side to go.
Code
/** * Forward declaration of guess API. * @param num your guess * @return -1 if num is higher than the picked number * 1 if num is lower than the picked number * otherwise return 0 * int guess(int num); */ public class Solution extends GuessGame { public int guessNumber(int n) { int left = 1; int right = n; while (left <= right) { int mid = left + (right - left) / 2; if (guess(mid) == 0) { return mid; } else if (guess(mid) == 1) { left = mid + 1; } else { right = mid - 1; } } return left - 1; } }